16x^2+33x+16=81

Solution for 16x^2+33x+16=81 equation:

16x^2+33x+16=81

We move all terms to the left:

16x^2+33x+16-(81)=0

We add all the numbers together, and all the variables

16x^2+33x-65=0

a = 16; b = 33; c = -65;
Δ = b2-4ac
Δ = 332-4·16·(-65)
Δ = 5249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-\sqrt{5249}}{2*16}=\frac{-33-\sqrt{5249}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+\sqrt{5249}}{2*16}=\frac{-33+\sqrt{5249}}{32}
$